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Further Pure Mathematics 1

Board Coverage

BoardPaperNotes
AQAPaper 2Complex numbers, matrices, series, proof
EdexcelFP1Complex numbers, matrices, polar coords, proof by induction
OCR (A)Pure Core 1Complex numbers, matrices, polar coords, hyperbolic
CIE (9709)Paper 3Complex numbers, polars, further calculus, induction

:::info This content sits at the transition between single A-Level Mathematics and Further Mathematics. You must be confident with all Core Pure topics before tackling these.


1. Complex Numbers

1.1 Argand Diagram

A complex number z=x+iyz = x + iy is represented as the point (x,y)(x, y) on the Argand diagram (a modified Cartesian plane where the horizontal axis is the real axis and the vertical axis is the imaginary axis).

  • The modulus z=r=x2+y2|z| = r = \sqrt{x^2 + y^2} is the distance from the origin to (x,y)(x, y).
  • The argument arg(z)=θ\arg(z) = \theta is the angle from the positive real axis, measured anticlockwise. Principal argument: π<θπ-\pi < \theta \leq \pi.

z=x+iy=r(cosθ+isinθ)=reiθz = x + iy = r(\cos\theta + i\sin\theta) = re^{i\theta}

1.2 Modulus-Argument Form

Multiplication: z1z2=r1r2ei(θ1+θ2)z_1 z_2 = r_1 r_2\,e^{i(\theta_1 + \theta_2)}. Moduli multiply; arguments add.

Division: z1z2=r1r2ei(θ1θ2)\dfrac{z_1}{z_2} = \dfrac{r_1}{r_2}\,e^{i(\theta_1 - \theta_2)}. Moduli divide; arguments subtract.

Modulus properties:

z1z2=z1z2z1+z2z1+z2zn=zn|z_1 z_2| = |z_1|\,|z_2| \qquad |z_1 + z_2| \leq |z_1| + |z_2| \qquad |z^n| = |z|^n

1.3 de Moivre’s Theorem

For integer nn:

[r(cosθ+isinθ)]n=rn(cosnθ+isinnθ)[r(\cos\theta + i\sin\theta)]^n = r^n(\cos n\theta + i\sin n\theta)

Equivalently: (eiθ)n=einθ(e^{i\theta})^n = e^{in\theta}.

Applications:

  • Raising complex numbers to large powers
  • Trigonometric identities (equating real and imaginary parts)

1.4 Roots of Unity

The nnth roots of unity are the solutions to zn=1z^n = 1:

zk=e2πik/n=cos2πkn+isin2πkn,k=0,1,2,,n1z_k = e^{2\pi i k / n} = \cos\frac{2\pi k}{n} + i\sin\frac{2\pi k}{n}, \quad k = 0, 1, 2, \ldots, n-1

They lie on the unit circle at vertices of a regular nn-gon. The sum of all nnth roots of unity is 00.

Example. The cube roots of unity are 11, ω=e2πi/3\omega = e^{2\pi i/3}, and ω2\omega^2. They satisfy 1+ω+ω2=01 + \omega + \omega^2 = 0 and ω3=1\omega^3 = 1.

1.5 Loci in the Complex Plane

Circle: zz0=r|z - z_0| = r represents a circle centred at z0z_0 with radius rr.

Perpendicular bisector: zz1=zz2|z - z_1| = |z - z_2| is the perpendicular bisector of the segment joining z1z_1 and z2z_2.

Half-line (ray): arg(zz0)=α\arg(z - z_0) = \alpha is a half-line from z0z_0 making angle α\alpha with the positive real axis.

Region inequalities: zz0<r|z - z_0| < r is the interior of a circle; arg(zz0)<α\arg(z - z_0) < \alpha is a region bounded by a half-line.


2. Matrices

2.1 Matrix Operations

Addition: A+BA + B elementwise (same dimensions required).

Scalar multiplication: kAkA multiplies every entry.

Matrix multiplication: (AB)ij=kAikBkj(AB)_{ij} = \sum_k A_{ik} B_{kj}. Number of columns of AA must equal number of rows of BB. As a general principle, ABBAAB \neq BA.

Identity: InI_n has 11s on the diagonal and 00s elsewhere. AI=IA=AAI = IA = A.

Determinant of 2×22 \times 2:

abcd=adbc\begin{vmatrix} a & b \\ c & d \end{vmatrix} = ad - bc

Inverse of 2×22 \times 2:

(abcd)1=1adbc(dbca)\begin{pmatrix} a & b \\ c & d \end{pmatrix}^{-1} = \frac{1}{ad-bc}\begin{pmatrix} d & -b \\ -c & a \end{pmatrix}

A matrix has an inverse if and only if its determinant is non-zero (it is non-singular).

2.2 Determinant of 3×33 \times 3

Expand by cofactors along any row or column. Along row 1:

abcdefghi=aefhibdfgi+cdegh\begin{vmatrix} a & b & c \\ d & e & f \\ g & h & i \end{vmatrix} = a\begin{vmatrix} e & f \\ h & i \end{vmatrix} - b\begin{vmatrix} d & f \\ g & i \end{vmatrix} + c\begin{vmatrix} d & e \\ g & h \end{vmatrix}

2.3 Inverse of 3×33 \times 3

Form the matrix of cofactors, transpose it (giving the adjugate), then divide by the determinant:

A1=1Aadj(A)A^{-1} = \frac{1}{|A|}\text{adj}(A)

Solving Ax=bA\mathbf{x} = \mathbf{b}: x=A1b\mathbf{x} = A^{-1}\mathbf{b} (unique solution when A0|A| \neq 0).

2.4 Transformations in 2D

A matrix MM represents a linear transformation. The image of point (x,y)(x, y) is M(xy)M\begin{pmatrix} x \\ y \end{pmatrix}.

TransformationMatrix
Reflection in y=xy = x(0110)\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}
Rotation θ\theta anticlockwise(cosθsinθsinθcosθ)\begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}
Enlargement scale factor kk(k00k)\begin{pmatrix} k & 0 \\ 0 & k \end{pmatrix}
Reflection in xx-axis(1001)\begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}

Area scale factor =det(M)= |\det(M)|.

2.5 Transformations in 3D

3×33 \times 3 matrices represent transformations in 3D space. Key examples:

  • Reflection in xyxy-plane: (100010001)\begin{pmatrix} 1&0&0\\0&1&0\\0&0&-1 \end{pmatrix}
  • Rotation about the zz-axis: extend the 2D rotation matrix to 3×33 \times 3 with a 11 in position (3,3)(3,3)

Volume scale factor =det(M)= |\det(M)|.

2.6 Invariant Points and Lines

An invariant point satisfies Mx=xM\mathbf{x} = \mathbf{x}, i.e. (MI)x=0(M - I)\mathbf{x} = \mathbf{0}.

An invariant line through the origin satisfies Mx=λxM\mathbf{x} = \lambda\mathbf{x} for some scalar λ\lambda. This means finding the eigenvectors of MM.

A line invariant as a set means every point on the line maps to some point on the same line (not necessarily itself).


3. Further Calculus

3.1 Integration by Parts

udv=uvvdu\int u\,dv = uv - \int v\,du

Choosing uu and dvdv: Use the LIATE priority: Logarithmic, Inverse trig, Algebraic, Trigonometric, Exponential. Choose uu from higher priority.

Repeated integration by parts is needed when the integrand includes products like xneaxx^n e^{ax}, xnsinaxx^n \sin ax, or xncosaxx^n \cos ax.

3.2 Standard Integrals

1x2+a2dx=1atan1xa+C1a2x2dx=sin1xa+C\int \frac{1}{x^2 + a^2}\,dx = \frac{1}{a}\tan^{-1}\frac{x}{a} + C \qquad \int \frac{1}{\sqrt{a^2 - x^2}}\,dx = \sin^{-1}\frac{x}{a} + C

1x2a2dx=12alnxax+a+C\int \frac{1}{x^2 - a^2}\,dx = \frac{1}{2a}\ln\left|\frac{x-a}{x+a}\right| + C

3.3 First Order Differential Equations

Separable form: dydx=f(x)g(y)\dfrac{dy}{dx} = f(x)g(y). Rearrange: 1g(y)dy=f(x)dx\dfrac{1}{g(y)}\,dy = f(x)\,dx, then integrate both sides.

Integrating factor method for dydx+P(x)y=Q(x)\dfrac{dy}{dx} + P(x)y = Q(x):

Integrating factor μ=eP(x)dx\text{Integrating factor } \mu = e^{\int P(x)\,dx}

yμ=Q(x)μdx+Cy \cdot \mu = \int Q(x)\mu\,dx + C

General solution: contains an arbitrary constant CC.

Particular solution: found by substituting initial conditions to determine CC.

3.4 Second Order Differential Equations

Homogeneous equation: ad2ydx2+bdydx+cy=0a\dfrac{d^2y}{dx^2} + b\dfrac{dy}{dx} + cy = 0

Auxiliary equation: am2+bm+c=0am^2 + bm + c = 0

Case 1 — Distinct real roots m1,m2m_1, m_2:

y=Aem1x+Bem2xy = Ae^{m_1 x} + Be^{m_2 x}

Case 2 — Repeated root mm:

y=(Ax+B)emxy = (Ax + B)e^{mx}

Case 3 — Complex roots α±iβ\alpha \pm i\beta:

y=eαx(Acosβx+Bsinβx)y = e^{\alpha x}(A\cos\beta x + B\sin\beta x)


4. Polar Coordinates

4.1 Converting Between Cartesian and Polar

A point with Cartesian coordinates (x,y)(x, y) and polar coordinates (r,θ)(r, \theta):

x=rcosθy=rsinθr=x2+y2tanθ=yxx = r\cos\theta \qquad y = r\sin\theta \qquad r = \sqrt{x^2 + y^2} \qquad \tan\theta = \frac{y}{x}

4.2 Sketching Polar Curves

Given r=f(θ)r = f(\theta):

  1. Determine the range of θ\theta (often 0θ2π0 \leq \theta \leq 2\pi or a subset).
  2. Find where r=0r = 0 and maxima of rr.
  3. Compute a table of (r,θ)(r, \theta) values at key angles (00, π/6\pi/6, π/4\pi/4, π/3\pi/3, π/2\pi/2, π\pi, 3π/23\pi/2, 2π2\pi).
  4. Plot each point and join smoothly.

Common curves:

EquationShape
r=ar = aCircle, radius aa, centre at origin
r=aθr = a\thetaArchimedean spiral
r=a(1+cosθ)r = a(1 + \cos\theta)Cardioid
r2=a2cos2θr^2 = a^2\cos 2\thetaLemniscate

4.3 Area Enclosed by a Polar Curve

A=12αβr2dθA = \frac{1}{2}\int_{\alpha}^{\beta} r^2\,d\theta

For a full curve traced once as θ\theta goes from α\alpha to β\beta, substitute the full range.

Sector area between two values θ1\theta_1 and θ2\theta_2:

A=12θ1θ2r2dθA = \frac{1}{2}\int_{\theta_1}^{\theta_2} r^2\,d\theta


5. Hyperbolic Functions

5.1 Definitions

coshx=ex+ex2sinhx=exex2tanhx=sinhxcoshx\cosh x = \frac{e^x + e^{-x}}{2} \qquad \sinh x = \frac{e^x - e^{-x}}{2} \qquad \tanh x = \frac{\sinh x}{\cosh x}

Key values: cosh0=1\cosh 0 = 1, sinh0=0\sinh 0 = 0, tanh0=0\tanh 0 = 0.

5.2 Identities

cosh2xsinh2x=1\cosh^2 x - \sinh^2 x = 1 1tanh2x=sech2x1 - \tanh^2 x = \text{sech}^2\, x coth2x1=cosech2x\coth^2 x - 1 = \text{cosech}^2\, x

Compound angle (Osborn’s rule): Replace every sin2\sin^2 with sinh2-\sinh^2 in a standard trig identity.

cosh(x+y)=coshxcoshy+sinhxsinhy\cosh(x + y) = \cosh x \cosh y + \sinh x \sinh y sinh(x+y)=sinhxcoshy+coshxsinhy\sinh(x + y) = \sinh x \cosh y + \cosh x \sinh y

5.3 Calculus of Hyperbolic Functions

ddxsinhx=coshxddxcoshx=sinhxddxtanhx=sech2x\frac{d}{dx}\sinh x = \cosh x \qquad \frac{d}{dx}\cosh x = \sinh x \qquad \frac{d}{dx}\tanh x = \text{sech}^2\, x

coshxdx=sinhx+Csinhxdx=coshx+C\int \cosh x\,dx = \sinh x + C \qquad \int \sinh x\,dx = \cosh x + C

5.4 Inverse Hyperbolic Functions

sinh1x=ln(x+x2+1)cosh1x=ln(x+x21) for x1\sinh^{-1} x = \ln\left(x + \sqrt{x^2 + 1}\right) \qquad \cosh^{-1} x = \ln\left(x + \sqrt{x^2 - 1}\right)\text{ for } x \geq 1

tanh1x=12ln1+x1x for x<1\tanh^{-1} x = \frac{1}{2}\ln\frac{1+x}{1-x}\text{ for } |x| < 1

Derivatives:

ddxsinh1x=11+x2ddxcosh1x=1x21\frac{d}{dx}\sinh^{-1} x = \frac{1}{\sqrt{1+x^2}} \qquad \frac{d}{dx}\cosh^{-1} x = \frac{1}{\sqrt{x^2-1}}


6. Proof

6.1 Proof by Induction (Advanced)

Steps:

  1. Base case: Show the statement holds for n=n0n = n_0 (in most cases n=1n = 1).
  2. Inductive hypothesis: Assume the statement holds for n=kn = k.
  3. Inductive step: Show that if it holds for n=kn = k, it also holds for n=k+1n = k + 1.
  4. Conclusion: By the principle of mathematical induction, the statement holds for all nn0n \geq n_0.

Common applications:

  • Summation formulas: r=1nr2=n(n+1)(2n+1)6\sum_{r=1}^{n} r^2 = \frac{n(n+1)(2n+1)}{6}
  • Divisibility: proving 32n13^{2n} - 1 is divisible by 8
  • Inequalities: 2n>n22^n > n^2 for n5n \geq 5
  • De Moivre’s theorem for positive integers
  • Matrix powers: AnA^n for a given matrix AA

6.2 Proof by Contradiction

  1. Assume the negation of the statement to be proved.
  2. Derive a logical contradiction.
  3. Conclude the original statement must be true.

Classic examples:

  • 2\sqrt{2} is irrational
  • There are infinitely many primes
  • log23\log_2 3 is irrational

6.3 Counterexamples

A single counterexample is sufficient to disprove a universal claim.

Example. “All prime numbers are odd.” Counterexample: 22 is prime and even.

Strategy: For disproof, try small values, boundary cases, and special cases to find a counterexample.


7. Common Mistakes

  1. Wrong principal argument. arg(z)\arg(z) must satisfy π<θπ-\pi < \theta \leq \pi. Points in the third and fourth quadrants need negative arguments.
  2. Forgetting rr when multiplying complex numbers in polar form. z1z2=r1r2ei(θ1+θ2)z_1 z_2 = r_1 r_2 e^{i(\theta_1+\theta_2)}, not ei(θ1+θ2)e^{i(\theta_1+\theta_2)}.
  3. Matrix multiplication is not commutative. ABBAAB \neq BA as a general principle. Always maintain order.
  4. Incorrect area formula for polar curves. It is 12r2dθ\frac{1}{2}\int r^2\,d\theta, not rdθ\int r\,d\theta.
  5. Confusing trig and hyperbolic identities. The key difference: cosh2xsinh2x=1\cosh^2 x - \sinh^2 x = 1 (minus, not plus). Use Osborn’s rule carefully.
  6. Incomplete induction step. You must explicitly show how the n=kn = k hypothesis is used to establish the n=k+1n = k + 1 case. Directly writing the n=k+1n = k + 1 expression is not enough.
  7. Incorrect auxiliary equation roots. For repeated roots, the solution is (Ax+B)emx(Ax + B)e^{mx}, not Aemx+BemxAe^{mx} + Be^{mx} (which is only valid for distinct real roots).

Worked Examples

Example 1: Solving a Second Order Differential Equation

Problem: Solve d2ydx25dydx+6y=0\dfrac{d^2y}{dx^2} - 5\dfrac{dy}{dx} + 6y = 0 given y(0)=1y(0) = 1 and y(0)=5y'(0) = 5. Solution: Auxiliary equation: m25m+6=0m^2 - 5m + 6 = 0, giving m=2m = 2 or m=3m = 3 (distinct real roots). y=Ae2x+Be3xy = Ae^{2x} + Be^{3x} y(0)=A+B=1y(0) = A + B = 1. y=2Ae2x+3Be3xy' = 2Ae^{2x} + 3Be^{3x}, so y(0)=2A+3B=5y'(0) = 2A + 3B = 5. Solving: B=3B = 3, A=2A = -2. Solution: y=3e3x2e2xy = 3e^{3x} - 2e^{2x}.

Example 2: Polar Curve Area

Problem: Find the area enclosed by one loop of the curve r=asin2θr = a\sin 2\theta. Solution: One loop is traced as θ\theta goes from 00 to π/2\pi/2 (where rr returns to zero). A=120π/2a2sin22θdθ=a220π/21cos4θ2dθ=a24[θsin4θ4]0π/2=a2π8A = \frac{1}{2}\int_0^{\pi/2} a^2\sin^2 2\theta\,d\theta = \frac{a^2}{2}\int_0^{\pi/2}\frac{1 - \cos 4\theta}{2}\,d\theta = \frac{a^2}{4}\left[\theta - \frac{\sin 4\theta}{4}\right]_0^{\pi/2} = \frac{a^2\pi}{8}

Common Pitfalls

  • Confusing the principal argument: For points in the third and fourth quadrants, the argument must be given as a negative angle (e.g., 3π/4-3\pi/4, not 5π/45\pi/4).
  • Matrix multiplication order: ABBAAB \neq BA. When solving Ax=bA\mathbf{x} = \mathbf{b}, compute A1bA^{-1}\mathbf{b}, not bA1\mathbf{b}A^{-1}.
  • Wrong polar area formula: Use 12r2dθ\frac{1}{2}\int r^2\,d\theta, not rdθ\int r\,d\theta. The extra r/2r/2 factor is frequently missed.

Summary

Further Pure 1 covers complex numbers (modulus-argument form, de Moivre, roots of unity, loci), matrices (operations, determinants, transformations, invariants), further calculus (integration by parts, standard integrals, first and second order ODEs), polar coordinates, hyperbolic functions, and proof techniques (induction, contradiction, counterexamples). Mastery of these topics is essential before progressing to Further Pure 2.

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